TO ESTIMATE THE AMOUNT OF BARIUM IN A SAMPLE OF BARIUM CHLORIDE GRAVIMETRICALLY

 APPARATUS REQUIRED

  • Cruible with lid
  • Desicator 
  • clay pipe triangle
  • wattman 40 ash less filterpaper 
  • funnel
  • Beaker 
  • Bunsen burner
  • Measuring cylinder 
  • Glass rod
  • Analytical balance
  • Fire Tong

CHEMICAL REQUIRED

  • Barrium chloride (0.3g)
  • 2N H2SO4
  •  Conc. HCL
  • Distilled water


THEORY

When a solution of known weight of barium
chloride (Bacl2•2H₂0)=244.36) is treated with an excess of dil. H2SO4, barrium is precipitated as Barium Sulfate. From the weight of Barium sulfate, amount of
barrium is calculated.

Bacl2 + H2So4 ➡️ BaSo4 + 2HCL

233.36g of BaSo4      = 137.369 of Barium 

Therefore, 1g. of Ba = 137.369÷233.36 g.

                                     = 0.5886g. of Ba.

During heating baso4, is slightly reduced with
carbon from fillter paper. So, finally a small
drop of Conc.H2So4 is added in the crucible to regain the reduced mass into the original
State

PROCEDURE

weight out of accurately 0.3g of hydrated barrium chloride (Bacl•2H2O). Tranfer
about it quantitatively in a 250ml of beaker. Add 100ml water and 1ml of HCL sheke well to dissolve and head to boiling. Add slowly with stiring an excess of 10ml of hot Solution of Bench H2SO4 Allow the precipitate to settle down test the supernatant liquid with H2SO4 to ensure complete precipitation allow it to cool. Transfer the precipitate with small portions of hot distilled water until free from (So4--) as tested with Bacl2 Solution cover the funnel with filter paper and dry the precipitate air oven tranfer the precepitate with in an Filter paper in a weighed crucible and ignite the pricipate as described. Head the crucible. again for 10-15 minute cool and weigh repeats the process until constant weight.

OBSERVATION AND CALCULATION

weight of Bacl2•2H2O taken = 0.3g
weight of empty crucible (w1): 44.06g
After ignition,
weight of crucible + BaSo4 (W2): 44.33g
weight of BaSo4      = W₂-w₁ 
                                   = 44.33- 14.06
                                   = 0.27g
observed weight of Ba in the Sample:
                                    = {137.36 ÷ 233.36}×0.27
                                    = 0.15898g.
Theo. wt. of Ba in the sample:
                                    = {137.36 ÷ 244.36}×0.27
                                    = 0.1686g of Ba.
therefore, % of experimental error
                                    = {10.1686-0.15891÷0.3}×100
                                    = 3.23%

RESULT

Hence, we observed 0.1686g of theatrical and 0.1589g observed wt. of barrium in given Sample.

CONCLUSION

We can estimate the amount of barrium in a given sample of barrium churide. 

TO DETERMINE THE AMOUNT OF IRON IN MOHR'S SALT AS IRON (lll) OXIDE


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