APPARATUS REQUIRED:
- conductometer
- Conductivity Cell
- Pipette
- Measuring cylinder.
- Burette
- Beaker
CHEMICAL REQUIRED
- CH3COOH Acetic acid
- NaOH Sodium Hydroxide
- Conductivity Water
THEORY
electrometric methods of measurement of concentration of an electrolyte soln by finding out conductances at various stage of titration. It's curve is obtained by plotting graphically, the conductance against the volume of sol" added from the burette. The point of break of the point of intersection in the Conductometeric titration curve gives the end point of titration.
CH3COOH ➡️ CH3COO- + H+
CH3COO- + H+ + Na+ + OH- ➡️ CH3COO- + Na+
+ H2O
conductance at zero addition of NAOH is low
on adding a small portion NAOH Solution.
on conductance the concentration of the reagent soln of the burette should be at least 10 times greater than the concentration of the solutions of the Conductivity bottle.
PROCEDURE
clean burette was filled with O.1N NaOH solution pipette 10ml of the given acetic acid solution 100ml clean beaker and add about some of to make it approximately to time more dilute than the solution of the burrette. Conductivity cell was plated of known cell constant by dipping electrodes completely in the acid solution. Connected the cell to the conductivity bridge. Now we hour for record the conductance of diluted acid at every 0.5 ml addition of NaOH Soln with constant stirring Near to the equivalent point 0.2ml portions of NaOH are preferred. Conductometric titration is continued until the titration curve can be traced out clearly.
OBSERVATION
Volume of acetic acid pipetted (v₂): 50ml
Titration table
RESULT FROM CT. CURVE
The point of intersection of the curve the volume of NaOH solution of complete Nentalization(V1) = 5.5ml
CALCULATION
Name of S2 N acetic acid=V1 ml of 0.1N NaOH
Therefore, S2 = {V1×0.1÷V2} NaOH
= {5×0.1÷50}
i.e. S2 = 0.5÷50
Therefore S2 = 0.011N
RESULT
The concentration of acetic acid (weak acid) was found to be 0.011N
CONCLUSION.
Thus, we can carry out the conductometric titration between weak acid (CH3COOH) and strong base (NaOH).
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